watt thermoelectric
2010
How do I calculate the number of watts required to cool a volume of air?
Hi,
I was wondering, how would I go about calculating the amount of power required from a peltier (thermoelectric cooler) module to cool a specific volume of air in a polystyrene Esky?
Cheers,
Max
Thanks for that.
If I understand correctly, to drop the temparture of a box from 23°C to -5°C (a 28°K drop) for a container that holds 6L (or 6000 cc or approx 0.23 moles of air) the formular would be:
0.23 x 8.31 x 28
Thus equaling 53J of energy
or a total of ~17.6 watts power to remove the heat in 3 seconds.
I wish I had’ve paid attention in science when I was in highschool.
To reduce the air temperature by ∆T ºK, you need to remove the amount of heat energy equal to W = n*cp*∆T, where n = no of moles of air, cp = the specific heat of air, 8.31 J/mole-ºK. Find the no of mole of air from the gas law P*V = n*R*T0,
n = P*V/R*T0
The power needed depends on how fast you want to cool it. P = W/t
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